[Bug 58122] New: WSAENOTSOCK error when calling winsock.Send() on duplicated socket

[WineHQ Bugzilla]

http://bugs.winehq.org/show_bug.cgi?id=58122

Bug ID: 58122
           Summary: WSAENOTSOCK error when calling winsock.Send() on
                    duplicated socket
           Product: Wine-staging
           Version: 10.4
          Hardware: x86-64
                OS: Linux
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: -unknown
          Assignee: [e-mail]
          Reporter: [e-mail]
                CC: [e-mail], [e-mail]
      Distribution: ---

Process A creates a listening socket, accepts an incoming connection, and
obtains a socket handle hSock.

Process A spawns Process B with the InheritHandles flag, passing its own
ProcessID and the socket handle hSock as command-line arguments.

Process B calls OpenProcess() to get a handle hSrcProcess for the given
ProcessID, then duplicates hSock into hDupSock using
DuplicateHandle(hSrcProcess, hSock, GetCurrentProcess(), &hDupSock, ...);
Process B successfully receives data from the duplicated socket using
winsock.recv(hDupSock, ...).

Process B attempts to send data via winsock.send(hDupSock, ...), but the call
fails with WSAENOTSOCK (10038) ("Socket operation on non-socket").

Process B then tries sending the same data using kernel32.WriteFile(hDupSock,
...), and this operation succeeds.

Why does send() fail while WriteFile() works on the same duplicated handle?